Sioux City coordinates
Iowa, United States
Latitude, Longitude: 42.5, -96.4003
Elevation: 1200 (ft)
Sioux City coordinates in different formats
| Format | Latitude, Longitude |
|---|---|
| Simple decimal standard | 42.5, -96.4003 |
| Decimal Degrees (DD) | 42.5° N, 96.4003° W |
| Degrees and Decimal Minutes (DDM) | 42°30′ N, 96°24.018′ W |
| Degrees, Minutes and Seconds (DMS) | 42°30′0″ N, 96°24′1.1″ W |
Where is Sioux City
Sioux City is located at latitude 42.5 and longitude -96.4003 at an elevation of 1200 feet above sea level.
City information
| City | Sioux City |
| Country | United States |
| State | Iowa |
| Population | 82,821 (2017) |
| Language | English |
| Currency | USD (Dollar) |