San Angelo coordinates

Texas, United States

Latitude, Longitude: 31.4638, -100.437
Elevation: 1843 (ft)

San Angelo coordinates in different formats

FormatLatitude, Longitude
Simple decimal standard31.4638, -100.437
Decimal Degrees (DD)31.4638° N, 100.437° W
Degrees and Decimal Minutes (DDM)31°27.828′ N, 100°26.22′ W
Degrees, Minutes and Seconds (DMS)31°27′49.7″ N, 100°26′13.2″ W

Where is San Angelo

San Angelo is located at latitude 31.4638 and longitude -100.437 at an elevation of 1843 feet above sea level.

City information

CitySan Angelo
CountryUnited States
StateTexas
Population100,450 (2017)
LanguageEnglish
CurrencyUSD (Dollar)