Port Arthur coordinates
Texas, United States
Latitude, Longitude: 29.8852, -93.9423
Elevation: 6 (ft)
Port Arthur coordinates in different formats
| Format | Latitude, Longitude |
|---|---|
| Simple decimal standard | 29.8852, -93.9423 |
| Decimal Degrees (DD) | 29.8852° N, 93.9423° W |
| Degrees and Decimal Minutes (DDM) | 29°53.112′ N, 93°56.538′ W |
| Degrees, Minutes and Seconds (DMS) | 29°53′6.7″ N, 93°56′32.3″ W |
Where is Port Arthur
Port Arthur is located at latitude 29.8852 and longitude -93.9423 at an elevation of 6 feet above sea level.
City information
| City | Port Arthur |
| Country | United States |
| State | Texas |
| Population | 55,340 (2017) |
| Language | English |
| Currency | USD (Dollar) |