Palm Harbor coordinates
Florida, United States
Latitude, Longitude: 28.0781, -82.7637
Elevation: 49 (ft)
Palm Harbor coordinates in different formats
| Format | Latitude, Longitude |
|---|---|
| Simple decimal standard | 28.0781, -82.7637 |
| Decimal Degrees (DD) | 28.0781° N, 82.7637° W |
| Degrees and Decimal Minutes (DDM) | 28°4.686′ N, 82°45.822′ W |
| Degrees, Minutes and Seconds (DMS) | 28°4′41.2″ N, 82°45′49.3″ W |
Where is Palm Harbor
Palm Harbor is located at latitude 28.0781 and longitude -82.7637 at an elevation of 49 feet above sea level.
City information
| City | Palm Harbor |
| Country | United States |
| State | Florida |
| Population | 57,439 (2011) |
| Language | English |
| Currency | USD (Dollar) |