Minot coordinates
North Dakota, United States
Latitude, Longitude: 48.2325, -101.296
Elevation: 1620 (ft)
Minot coordinates in different formats
| Format | Latitude, Longitude |
|---|---|
| Simple decimal standard | 48.2325, -101.296 |
| Decimal Degrees (DD) | 48.2325° N, 101.296° W |
| Degrees and Decimal Minutes (DDM) | 48°13.95′ N, 101°17.76′ W |
| Degrees, Minutes and Seconds (DMS) | 48°13′57″ N, 101°17′45.6″ W |
Where is Minot
Minot is located at latitude 48.2325 and longitude -101.296 at an elevation of 1620 feet above sea level.
City information
| City | Minot |
| Country | United States |
| State | North Dakota |
| Population | 49,450 (2017) |
| Language | English |
| Currency | USD (Dollar) |