Fargo coordinates
North Dakota, United States
Latitude, Longitude: 46.8772, -96.7898
Elevation: 905 (ft)
Fargo coordinates in different formats
| Format | Latitude, Longitude |
|---|---|
| Simple decimal standard | 46.8772, -96.7898 |
| Decimal Degrees (DD) | 46.8772° N, 96.7898° W |
| Degrees and Decimal Minutes (DDM) | 46°52.632′ N, 96°47.388′ W |
| Degrees, Minutes and Seconds (DMS) | 46°52′37.9″ N, 96°47′23.3″ W |
Where is Fargo
Fargo is located at latitude 46.8772 and longitude -96.7898 at an elevation of 905 feet above sea level.
City information
| City | Fargo |
| Country | United States |
| State | North Dakota |
| Population | 118,523 (2017) |
| Language | English |
| Currency | USD (Dollar) |