Brownsville coordinates
New York, United States
Latitude, Longitude: 40.6609, -73.9201
Elevation: 29 (ft)
Brownsville coordinates in different formats
| Format | Latitude, Longitude |
|---|---|
| Simple decimal standard | 40.6609, -73.9201 |
| Decimal Degrees (DD) | 40.6609° N, 73.9201° W |
| Degrees and Decimal Minutes (DDM) | 40°39.654′ N, 73°55.206′ W |
| Degrees, Minutes and Seconds (DMS) | 40°39′39.2″ N, 73°55′12.4″ W |
Where is Brownsville
Brownsville is located at latitude 40.6609 and longitude -73.9201 at an elevation of 29 feet above sea level.
City information
| City | Brownsville |
| Country | United States |
| State | New York |
| Population | 74,497 (2017) |
| Language | English |
| Currency | USD (Dollar) |